If the earth stops rotating,the value of 'g' | vedclass

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(B) The effective acceleration due to gravity '$g'$ at the equator is given by the formula: $g' = g - R\omega^2$,where '$g$' is the acceleration due t

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increase

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(B) The effective acceleration due to gravity '$g'$ at the equator is given by the formula: $g' = g - R\omega^2$,where '$g$' is the acceleration due to gravity at the poles (or if the earth were stationary),'$R$' is the radius of the earth,and '$\omega$' is the angular velocity of the earth's rotation.If the earth stops rotating,the angular velocity '$\omega$' becomes $0$.Substituting this into the formula,we get: $g' = g - R(0)^2 = g$.Since the original value was $g' = g - R\omega^2$ (which is less than '$g$'),the new value '$g$' is greater than the original value '$g'$ at the equator.Therefore,the value of '$g$' at the equator will increase.

If the earth stops rotating,the value of '$g$' at the equator will:

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