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(A) Given,the first term $a = -5$ and the common difference $d = 2$.We need to find the sum of the first $n = 6$ terms.The formula for the sum of the

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(A) Given,the first term $a = -5$ and the common difference $d = 2$.We need to find the sum of the first $n = 6$ terms.The formula for the sum of the first $n$ terms of an $AP$ is $S_{n} = \frac{n}{2} [2a + (n - 1)d]$.Substituting the values $n = 6$,$a = -5$,and $d = 2$ into the formula:$S_{6} = \frac{6}{2} [2(-5) + (6 - 1)(2)]$$S_{6} = 3 [-10 + 5(2)]$$S_{6} = 3 [-10 + 10]$$S_{6} = 3(0) = 0$.Thus,the sum of the first $6$ terms is $0$.

If the first term of an $AP$ is $-5$ and the common difference is $2,$ then the sum of the first $6$ terms is

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