If the function $f(x)=\sqrt{x^2-4}$ satisfies the Lagrange's mean value theorem on $[2, 4]$,then the value of $C$ is

  • A
    $2 \sqrt{3}$
  • B
    $-2 \sqrt{3}$
  • C
    $\sqrt{6}$
  • D
    $-\sqrt{6}$

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