If the interest on ₹ 12000 is more than the i | vedclass

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(C) Let the rate of interest be $R \%$ per annum.Simple Interest formula is $SI = \frac{P 	imes R 	imes T}{100}$.According to the problem,the differ

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$8 \frac{1}{3} \%$

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(C) Let the rate of interest be $R \%$ per annum.Simple Interest formula is $SI = \frac{P 	imes R 	imes T}{100}$.According to the problem,the difference in interest is ₹ $500$ for a time period of $3$ $years$.Difference in interest $= SI_1 - SI_2 = 500$.$\frac{12000 	imes R 	imes 3}{100} - \frac{10000 	imes R 	imes 3}{100} = 500$.$\frac{3R}{100} (12000 - 10000) = 500$.$\frac{3R}{100} (2000) = 500$.$3R 	imes 20 = 500$.$60R = 500$.$R = \frac{500}{60} = \frac{50}{6} = 8 \frac{1}{3} \%$.

If the interest on ₹ $12000$ is more than the interest on ₹ $10000$ by ₹ $500$ in $3$ $years$,the rate percent per annum is:

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