A sum of ₹ 2800 is divided into two parts in | vedclass

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(B) Let the first part be $₹ x$. Then the second part is $₹ (2800 - x)$.Since the simple interest on both parts is equal,we use the formula $SI = \fra

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₹ $1600$,₹ $1200$

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(B) Let the first part be $₹ x$. Then the second part is $₹ (2800 - x)$.Since the simple interest on both parts is equal,we use the formula $SI = \frac{P 	imes R 	imes T}{100}$.$\frac{x 	imes 9 	imes 5}{100} = \frac{(2800 - x) 	imes 10 	imes 6}{100}$$45x = (2800 - x) 	imes 60$Dividing both sides by $15$:$3x = (2800 - x) 	imes 4$$3x = 11200 - 4x$$7x = 11200$$x = 1600$Therefore,the first part is $₹ 1600$ and the second part is $2800 - 1600 = ₹ 1200$.

$A$ sum of ₹ $2800$ is divided into two parts in such a way that the interest on both the parts is equal. If the first part is lent at $9 \% \text{ p.a.}$ for $5 \text{ years}$ and the second part is for $6 \text{ years}$ at $10 \% \text{ p.a.}$,find the two sums.

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