If the length of the tangent from $(f, g)$ to the circle $x^2+y^2=6$ is twice the length of the tangent from the same point to the circle $x^2+y^2+3x+3y=0$,then $f^2+g^2+4f+4g+2$ is equal to

  • A
    $-1$
  • B
    $1$
  • C
    $0$
  • D
    $-2$

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