If the mass number of an atom is $A = 40$ and its electron configuration is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6$,the number of neutrons and protons in its nucleus will be
- A$22, 18$
- B$18, 22$
- C$20, 20$
- D$18, 18$
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