If the number of common tangents to the pair of circles $x^2+y^2-2x+4y-4=0$ and $x^2+y^2+4x-4y+\alpha=0$ is $4$,then the least integral value of $\alpha$ is

  • A
    $4$
  • B
    $5$
  • C
    $6$
  • D
    $7$

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