If the partial fraction decomposition of $\frac{x^4+24x^2+28}{(x^2+1)^3}$ is $\frac{A}{x^2+1}+\frac{B}{(x^2+1)^2}+\frac{C}{(x^2+1)^3}$,then $B-2A+C=$

  • A
    $23$
  • B
    $24$
  • C
    $25$
  • D
    $26$

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