If the points $(x + 1, 2)$,$(1, x + 2)$,and $\left( \frac{1}{x + 1}, \frac{2}{x + 1} \right)$ are collinear,then $x$ is

  • A
    $4$
  • B
    $0$
  • C
    $-4$
  • D
    Both $(b)$ and $(c)$

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