If the present age of $X$ is half that of $Y$ and after $20$ years the age of $Y$ will be $1 \frac{1}{2}$ times that of $X$,what is the present age of $X$?

The ratio of the present ages of Sunil and Suresh is $2:3$. Four years ago,their age ratio was $5:8$. Find the present ages of Sunil and Suresh (in $years$).

$A$ person was asked to state his age in years. His reply was "Take my age three years hence,multiply it by $3$ and then subtract three times my age three years ago and you will know how old $I$ am". What was the age of the person? (in years)

The ages of $A, B$ and $C$ together is $185$ years. $B$ is twice as old as $A$ and $C$ is $17$ years older than $A$. Then,the respective ages of $A, B$ and $C$ are (in years):

$7$ years ago,the ages (in years) of $A$ and $B$ were in the ratio $4:5$; and $7$ years hence they will be in the ratio $5:6$. The present age of $B$ is (in years):

$10$ years ago,Mohan was thrice as old as Ram was,but $10$ years hence,he will be only twice as old as Ram. Find Mohan's present age (in years).