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(B) The mean free path $\lambda$ of a gas molecule is given by the formula $\lambda = \frac{1}{\sqrt{2} \pi d^2 n}$,where $d$ is the diameter of the m

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Is increased

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(B) The mean free path $\lambda$ of a gas molecule is given by the formula $\lambda = \frac{1}{\sqrt{2} \pi d^2 n}$,where $d$ is the diameter of the molecule and $n$ is the number density (number of molecules per unit volume).Since the pressure $P$ of an ideal gas is related to the number density by $P = nkT$,reducing the pressure at a constant temperature implies that the number density $n$ decreases.As $n$ is in the denominator of the expression for $\lambda$,a decrease in $n$ leads to an increase in the mean free path $\lambda$.Therefore,when gas is drawn out of a closed vessel,the mean free path of the molecules increases.

If the pressure in a closed vessel is reduced by drawing out some gas,the mean free path of the molecules

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