(A) We are given the ratio $\frac{R}{C_v} = 0.67$.We know that the Mayer's relation is $C_p - C_v = R$,which can be written as $\frac{C_p}{C_v} - 1 =

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(A) We are given the ratio $\frac{R}{C_v} = 0.67$.We know that the Mayer's relation is $C_p - C_v = R$,which can be written as $\frac{C_p}{C_v} - 1 = \frac{R}{C_v}$.Let $\gamma = \frac{C_p}{C_v}$ be the adiabatic index.Then,$\gamma - 1 = 0.67$,which implies $\gamma = 1.67$.For a monoatomic gas,$\gamma = \frac{5}{3} \approx 1.67$.For a diatomic gas,$\gamma = \frac{7}{5} = 1.4$.For a polyatomic gas,$\gamma Since $\gamma = 1.67$,the gas is monoatomic.

Class 11 Physics Kinetic Theory of Gases Molar Specific Heat of gas and relation between them (Mayer's formula)

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If the ratio of the universal gas constant $(R)$ and the specific heat capacity at constant volume $(C_v)$ of a gas is given by $0.67$,then the gas is

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monoatomic
B
diatomic
C
polyatomic
D
a mixture of diatomic and polyatomic gases

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Kinetic Theory of Gases

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Molar Specific Heat of gas and relation between them (Mayer's formula)

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