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(C) Given that $\alpha$ and $\beta$ are the roots of the equation $ax^2 + bx + c = 0$.From the properties of quadratic equations,we have:$\alpha + \be

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$\frac{1}{\alpha}, \frac{1}{\beta}$

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(C) Given that $\alpha$ and $\beta$ are the roots of the equation $ax^2 + bx + c = 0$.From the properties of quadratic equations,we have:$\alpha + \beta = -\frac{b}{a}$ and $\alpha\beta = \frac{c}{a}$.Now,consider the equation $cx^2 + bx + a = 0$. Let its roots be $\alpha'$ and $\beta'$.For this equation,the sum of roots is $\alpha' + \beta' = -\frac{b}{c}$ and the product of roots is $\alpha'\beta' = \frac{a}{c}$.We can express the sum of the reciprocals of the original roots as:$\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha\beta} = \frac{-b/a}{c/a} = -\frac{b}{c}$.Also,the product of the reciprocals is:$\frac{1}{\alpha} \cdot \frac{1}{\beta} = \frac{1}{\alpha\beta} = \frac{1}{c/a} = \frac{a}{c}$.Since the sum and product of the roots $\frac{1}{\alpha}$ and $\frac{1}{\beta}$ match the sum and product of the roots of the equation $cx^2 + bx + a = 0$,the roots are $\frac{1}{\alpha}$ and $\frac{1}{\beta}$.

If the roots of the equation $ax^2 + bx + c = 0$ are $\alpha$ and $\beta$,then the roots of the equation $cx^2 + bx + a = 0$ are

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