If the screen is moved away from the plane of the slits in a Young's double slit experiment,then the

In Young's double-slit experiment,if the distance between the slits is twice the wavelength,the number of possible interference maxima is:

Given below are two statements:
Statement $I$: In a Young's double slit experiment, the angular separation of fringes will increase as the screen is moved away from the plane of the slits.
Statement $II$: In a Young's double slit experiment, the angular separation of fringes will increase when a monochromatic source is replaced by another monochromatic source of higher wavelength.
In the light of the above statements, choose the correct answer from the options given below:

In a Young's double-slit experiment,the light beam consists of two wavelengths $6500 \, \mathring{A}$ and $5200 \, \mathring{A}$. The distance between the slits is $2 \, mm$ and the distance between the plane of the slits and the screen is $120 \, cm$. What is the minimum distance from the central maximum where the bright fringes of both wavelengths coincide (in $, cm$)?

In a double slit experiment,when the distance between slits is increased $10$ times,while their distance from the screen is halved,then the fringe width

In Young's double slit experiment,the intensity at a point is $1/4$ of the maximum intensity. The angular position of this point is: