If the shortest distance from $(2,-14)$ to the circle $x^2+y^2+6x+4y-12=0$ is $d$ and the length of the tangent drawn from the same point to the circle is $l$,then $\sqrt{d+l}=$

  • A
    $13$
  • B
    $2\sqrt{5}$
  • C
    $12$
  • D
    $5$

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