If the slope of the tangent on a curve at any point $(x, y)$ is equal to $\frac{y^2-x^2}{2xy}$,then the equation of the normal at the point $\left(\frac{1}{2}, \frac{\sqrt{3}}{2}\right)$ is

  • A
    $\sqrt{3}x + y = \sqrt{3}$
  • B
    $x + \sqrt{3}y = \sqrt{3}$
  • C
    $3x - \sqrt{3}y = 0$
  • D
    $x + \sqrt{3}y = 0$

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