If the statement pattern (p wedge q) rightarr | vedclass

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(D) The implication $(p \wedge q) \rightarrow (r \vee \sim s)$ is false only when the antecedent $(p \wedge q)$ is true and the consequent $(r \vee \s

Vedclass · Accepted Answer

$T, T, F, T$

Vedclass · Answer

(D) The implication $(p \wedge q) \rightarrow (r \vee \sim s)$ is false only when the antecedent $(p \wedge q)$ is true and the consequent $(r \vee \sim s)$ is false.For $(p \wedge q)$ to be true,both $p$ and $q$ must be true $(T)$.For $(r \vee \sim s)$ to be false,both $r$ and $\sim s$ must be false $(F)$.Since $\sim s$ is false,$s$ must be true $(T)$.Therefore,the truth values are $p = T, q = T, r = F, s = T$.

If the statement pattern $(p \wedge q) \rightarrow (r \vee \sim s)$ is false,then the truth values of $p, q, r$ and $s$ are respectively:

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