If the students of 9^{th} class are arranged | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To find the number of students that can be arranged in rows of $6, 8, 12$,or $16$ without any student being left behind,we need to find the Least

Vedclass · Accepted Answer

$96$

Vedclass · Answer

(D) To find the number of students that can be arranged in rows of $6, 8, 12$,or $16$ without any student being left behind,we need to find the Least Common Multiple $(L.C.M.)$ of these numbers.$L.C.M.$ of $6, 8, 12, 16$:$2$$6, 8, 12, 16$$2$$3, 4, 6, 8$$2$$3, 2, 3, 4$$2$$3, 1, 3, 2$$3$$3, 1, 3, 1$$1, 1, 1, 1$$L.C.M. = 2 	imes 2 	imes 2 	imes 2 	imes 3 = 48$.The number of students must be a multiple of $48$. Among the given options,$96$ is a multiple of $48$ $(48 	imes 2 = 96)$.

If the students of $9^{th}$ class are arranged in rows of $6, 8, 12$ or $16$,no student is left behind. The possible number of students in the class is

Similar Questions

Three numbers which are co-prime to each other are such that the product of the first two is $551$ and that of the last two is $1073$. The sum of the three numbers is:

The $H.C.F.$ of two numbers is $12$ and their difference is $12$. The numbers are:

The $LCM$ of $22, 54, 108, 135$ and $198$ is

The product of two $2$-digit numbers is $2160$ and their $H.C.F.$ is $12$. The numbers are:

The product of two numbers is $4107$. If the $HCF$ of these numbers is $37$,then the greater number is

Vedclass Test Series

Exam Paper Generator

Online Exam Module