If the two circles $2x^2 + 2y^2 - 3x + 6y + k = 0$ and $x^2 + y^2 - 4x + 10y + 16 = 0$ cut orthogonally,then the value of $k$ is

  • A
    $41$
  • B
    $14$
  • C
    $4$
  • D
    $0$

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