If the values $x=\alpha, y=\beta, z=\gamma$ satisfy all the $3$ equations $x+2y+3z=4$,$3x+y+z=3$ and $x+3y+3z=2$,then $3\alpha+\gamma=$

  • A
    $\beta$
  • B
    $2\beta$
  • C
    $1-2\beta$
  • D
    $2\beta+1$

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