If the variance of the distribution is $45.8$,then find the variance of the distribution given below:
$x_i$ $4$ $8$ $11$ $17$ $20$ $24$ $32$
$f_i$ $3$ $5$ $9$ $5$ $4$ $3$ $1$

$y_i$ $10$ $18$ $24$ $36$ $42$ $50$ $66$
$f_i$ $3$ $5$ $9$ $5$ $4$ $3$ $1$

  • A
    $93.6$
  • B
    $\sqrt{93.9}$
  • C
    $183.2$
  • D
    $\sqrt{183.2}$

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The mean square deviation of a set of observations $x_1, x_2, \dots, x_n$ about a point $c$ is defined as $\frac{1}{n} \sum_{i=1}^n (x_i - c)^2$. If the mean square deviations about $-2$ and $2$ are $18$ and $10$ respectively,find the standard deviation of this set of observations.

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Students of two sections $A$ and $B$ of a class show the following results in a test conducted for $100$ marks. Then
Section $A$ Section $B$
Number of students $50$ $60$
Average marks in the test $45$ $45$
Variance of distribution of marks $64$ $81$

Find the mean and variance for the following frequency distribution:
Classes $0-30$ $30-60$ $60-90$ $90-120$ $120-150$ $150-180$ $180-210$
$f_i$ $2$ $3$ $5$ $10$ $3$ $5$ $2$

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Let $\sigma_1$ and $\sigma_2$ be the standard deviations of two distributions $D_1$ and $D_2$ respectively,and $D_1$ be more consistent than $D_2$. If the means of $D_1$ and $D_2$ are the same,then the percentage increase in the standard deviation of $D_2$ over the standard deviation of $D_1$ is:

Let the observations $x_{i} (1 \leq i \leq 10)$ satisfy the equations $\sum_{i=1}^{10}(x_{i}-5)=10$ and $\sum_{i=1}^{10}(x_{i}-5)^{2}=40$. If $\mu$ and $\lambda$ are the mean and the variance of the observations $x_{1}-3, x_{2}-3, \dots, x_{10}-3$,then the ordered pair $(\mu, \lambda)$ is equal to:

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