If the vector $a = 2 \hat{i} + 3 \hat{j} + 6 \hat{k}$ and $b$ are collinear and $|b| = 21$, then $b$ is equal to:
- A$\pm(2 \hat{i} + 3 \hat{j} + 6 \hat{k})$
- B$\pm 3(2 \hat{i} + 3 \hat{j} + 6 \hat{k})$
- C$(\hat{i} + \hat{j} + \hat{k})$
- D$\pm 21(2 \hat{i} + 3 \hat{j} + 6 \hat{k})$
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