If the transmission power of a surface is fra | vedclass

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(B) For any surface,the sum of the transmission power $(t)$,reflective power $(r)$,and absorptive power $(a)$ is equal to $1$.$t + r + a = 1$Given tha

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$\frac{13}{18}$

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(B) For any surface,the sum of the transmission power $(t)$,reflective power $(r)$,and absorptive power $(a)$ is equal to $1$.$t + r + a = 1$Given that $t = \frac{1}{9}$ and $r = \frac{1}{6}$,we can substitute these values into the equation:$a = 1 - (t + r)$$a = 1 - \left(\frac{1}{9} + \frac{1}{6}\right)$To add the fractions,find the least common multiple of $9$ and $6$,which is $18$:$a = 1 - \left(\frac{2}{18} + \frac{3}{18}\right)$$a = 1 - \frac{5}{18}$$a = \frac{18 - 5}{18} = \frac{13}{18}$

If the transmission power of a surface is $\frac{1}{9}$ and the reflective power is $\frac{1}{6}$,then what is its absorptive power?

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