If two bodies A and B of equal masses M are s | vedclass

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(B) The initial gravitational force between the two bodies is given by $F = \frac{G M^2}{d^2}$.After transferring $50 \%$ of the mass from $A$ to $B$,

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$3 F$

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(B) The initial gravitational force between the two bodies is given by $F = \frac{G M^2}{d^2}$.After transferring $50 \%$ of the mass from $A$ to $B$,the new masses are $M_A = M - 0.5 M = 0.5 M = \frac{M}{2}$ and $M_B = M + 0.5 M = 1.5 M = \frac{3 M}{2}$.The new distance between the bodies is $d' = \frac{d}{2}$.The gravitational force is independent of the medium between the bodies.Therefore,the new gravitational force $F'$ is given by $F' = \frac{G M_A M_B}{(d')^2} = \frac{G (M/2) (3M/2)}{(d/2)^2}$.$F' = \frac{3 G M^2 / 4}{d^2 / 4} = \frac{3 G M^2}{d^2}$.Since $F = \frac{G M^2}{d^2}$,we get $F' = 3 F$.

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