If two events $A$ and $B$ are such that $P(\overline{A}) = 0.3$,$P(B) = 0.4$,and $P(A \cap \overline{B}) = 0.5$,then $P(B | (A \cup \overline{B})) = $

  • A
    $0.25$
  • B
    $0.6$
  • C
    $0.45$
  • D
    $0.8$

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