If two molecules of A and B have molar masses | vedclass

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(A) According to Graham's law of diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $\frac{r_A}{r

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$15 	imes 10^{-3}$

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(A) According to Graham's law of diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $\frac{r_A}{r_B} = \sqrt{\frac{M_B}{M_A}}$ Given: $M_A = 100 \ g/mol$ $M_B = 64 \ g/mol$ $r_A = 12 	imes 10^{-3} \ mol/s$ Substituting the values: $\frac{12 	imes 10^{-3}}{r_B} = \sqrt{\frac{64}{100}}$ $\frac{12 	imes 10^{-3}}{r_B} = \frac{8}{10} = 0.8$ $r_B = \frac{12 	imes 10^{-3}}{0.8} = 15 	imes 10^{-3} \ mol/s$

If two molecules of $A$ and $B$ have molar masses of $100 \ g/mol$ and $64 \ g/mol$ respectively,and the rate of diffusion of $A$ is $12 \times 10^{-3} \ mol/s$,then the rate of diffusion of $B$ will be:

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