If two tuning forks A and B are sounded toget | vedclass

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(B) Given: Frequency of tuning fork $A$ $(n_A)$ = $256 \ Hz$. Initial beat frequency $(x)$ = $4 \ Hz$. When $A$ is loaded with wax,its frequency decre

Vedclass · Accepted Answer

$252$

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(B) Given: Frequency of tuning fork $A$ $(n_A)$ = $256 \ Hz$. Initial beat frequency $(x)$ = $4 \ Hz$. When $A$ is loaded with wax,its frequency decreases $(n_A \downarrow)$. New beat frequency $(x')$ = $2 \ Hz$. Since the beat frequency decreases from $4 \ Hz$ to $2 \ Hz$ upon loading $A$,the initial condition must be $n_A - n_B = x$. Substituting the values: $256 - n_B = 4$,which gives $n_B = 252 \ Hz$. Verification: After loading $A$,$n_A$ becomes less than $256$. Let the new frequency be $n_A'$. Then $n_A' - n_B = 2$. Since $n_B = 252$,$n_A' = 254 \ Hz$. This is consistent with the frequency of $A$ decreasing. Therefore,the frequency of $B$ is $252 \ Hz$.

If two tuning forks $A$ and $B$ are sounded together,they produce $4$ beats per second. $A$ is then slightly loaded with wax,and they produce $2$ beats when sounded again. The frequency of $A$ is $256 \ Hz$. The frequency of $B$ will be: (in $Hz$)

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