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(C) The magnetic field $B$ on the axis of a circular coil of radius $R$ at a large distance $x$ $(x \gg R)$ from the center is given by the formula:$B

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(C) The magnetic field $B$ on the axis of a circular coil of radius $R$ at a large distance $x$ $(x \gg R)$ from the center is given by the formula:$B_{	ext{axis}} = \frac{\mu_{0} N I R^{2}}{2 x^{3}}$From this expression,we can see that the magnetic field is directly proportional to the square of the radius of the coil:$B \propto R^{2}$If the radius $R$ is doubled $(R' = 2R)$,the new magnetic field $B'$ becomes:$B' \propto (2R)^{2} = 4R^{2}$Therefore,$B' = 4B$.Thus,the magnetic field becomes four times the original value.

If we double the radius of a coil keeping the current through it unchanged,then the magnetic field at any point at a large distance from the centre becomes approximately

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