If Zeba were younger by 5, text{years} than w | vedclass

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(C) Let the actual age of Zeba be $x\, 	ext{years}$.Her age when she was $5\, 	ext{years}$ younger is $(x - 5)\, 	ext{years}$.According to the give

Vedclass · Accepted Answer

$14$

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(C) Let the actual age of Zeba be $x\, 	ext{years}$.Her age when she was $5\, 	ext{years}$ younger is $(x - 5)\, 	ext{years}$.According to the given condition:$(x - 5)^2 = 5x + 11$Expanding the left side:$x^2 - 10x + 25 = 5x + 11$Rearranging the terms to form a quadratic equation:$x^2 - 10x - 5x + 25 - 11 = 0$$x^2 - 15x + 14 = 0$Factoring the quadratic equation by splitting the middle term:$x^2 - 14x - x + 14 = 0$$x(x - 14) - 1(x - 14) = 0$$(x - 1)(x - 14) = 0$This gives two possible values for $x$: $x = 1$ or $x = 14$.If $x = 1$, then her age $5\, 	ext{years}$ ago would be $1 - 5 = -4$, which is impossible as age cannot be negative.Therefore, the actual age of Zeba is $14\, 	ext{years}$.

If Zeba were younger by $5\, \text{years}$ than what she really is, then the square of her age (in years) would have been $11$ more than five times her actual age. What is her age now? (in $\text{years}$)

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