In Delta XYZ,angle Y = 90^{circ} and XY = YZ, | vedclass

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(C) In $\Delta XYZ$,we are given that $\angle Y = 90^{\circ}$.Since the sum of all angles in a triangle is $180^{\circ}$,we have $\angle X + \angle Y

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(C) In $\Delta XYZ$,we are given that $\angle Y = 90^{\circ}$.Since the sum of all angles in a triangle is $180^{\circ}$,we have $\angle X + \angle Y + \angle Z = 180^{\circ}$.Substituting the value of $\angle Y$,we get $\angle X + 90^{\circ} + \angle Z = 180^{\circ}$,which implies $\angle X + \angle Z = 90^{\circ}$.We are also given that $XY = YZ$. In a triangle,angles opposite to equal sides are equal.Therefore,$\angle Z = \angle X$.Substituting $\angle Z = \angle X$ into the equation $\angle X + \angle Z = 90^{\circ}$,we get $\angle X + \angle X = 90^{\circ}$.This simplifies to $2\angle X = 90^{\circ}$,which gives $\angle X = 45^{\circ}$.

In $\Delta XYZ$,$\angle Y = 90^{\circ}$ and $XY = YZ$,then $\angle X = \dots$ (in $^{\circ}$)

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