In Delta ABC,P,Q,and R are the midpoints of A | vedclass

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(A) According to the Midpoint Theorem,the line segment joining the midpoints of two sides of a triangle is parallel to the third side and is half the

Vedclass · Accepted Answer

$13.8$

Vedclass · Answer

(A) According to the Midpoint Theorem,the line segment joining the midpoints of two sides of a triangle is parallel to the third side and is half the length of the third side.In $\Delta ABC$,$P$ and $R$ are midpoints of $AB$ and $AC$ respectively,so $PR = \frac{1}{2} BC = \frac{9}{2} = 4.5 	ext{ cm}$.Similarly,$PQ = \frac{1}{2} AC = \frac{10.6}{2} = 5.3 	ext{ cm}$.And $QR = \frac{1}{2} AB = \frac{8}{2} = 4 	ext{ cm}$.The perimeter of $\Delta PQR = PQ + QR + PR = 5.3 + 4 + 4.5 = 13.8 	ext{ cm}$.

In $\Delta ABC$,$P$,$Q$,and $R$ are the midpoints of $AB$,$BC$,and $AC$ respectively. If $AB = 8 \text{ cm}$,$BC = 9 \text{ cm}$,and $AC = 10.6 \text{ cm}$,find the perimeter of $\Delta PQR$ in $\text{cm}$.

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