In $\Delta PQR$,$PM$ is a median. If $\text{ar}(\Delta PMQ) = 36 \text{ cm}^2$,then find $\text{ar}(\Delta PMR)$ in $\text{cm}^2$.

  • A
    $53$
  • B
    $50$
  • C
    $36$
  • D
    $75$

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