In Delta ABC,AB = 17,BC = 15,and AC = 8. Then | vedclass

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(A) Given sides of $\Delta ABC$ are $AB = 17$,$BC = 15$,and $AC = 8$.First,check if the triangle is a right-angled triangle using the converse of the

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$8.5$

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(A) Given sides of $\Delta ABC$ are $AB = 17$,$BC = 15$,and $AC = 8$.First,check if the triangle is a right-angled triangle using the converse of the Pythagorean theorem.$BC^2 + AC^2 = 15^2 + 8^2 = 225 + 64 = 289$.$AB^2 = 17^2 = 289$.Since $BC^2 + AC^2 = AB^2$,$\Delta ABC$ is a right-angled triangle with the hypotenuse $AB = 17$.The longest side of a right-angled triangle is its hypotenuse.According to the property of a right-angled triangle,the length of the median drawn to the hypotenuse is half the length of the hypotenuse.Length of median = $\frac{1}{2} 	imes AB = \frac{1}{2} 	imes 17 = 8.5$.

In $\Delta ABC$,$AB = 17$,$BC = 15$,and $AC = 8$. Then,the length of the median on the longest side of the triangle is $\ldots$.

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