(B) In any triangle $ABC$,the sum of angles is $A + B + C = 180^{\circ}$.Therefore,$\sin(A + B) = \sin(180^{\circ} - C) = \sin C$.Substituting this in

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(B) In any triangle $ABC$,the sum of angles is $A + B + C = 180^{\circ}$.Therefore,$\sin(A + B) = \sin(180^{\circ} - C) = \sin C$.Substituting this into the expression,we get $\frac{\sin B}{\sin(A + B)} = \frac{\sin B}{\sin C}$.By the Sine Rule,$\frac{b}{\sin B} = \frac{c}{\sin C}$,which implies $\frac{\sin B}{\sin C} = \frac{b}{c}$.Thus,the correct option is $B$.

Class 11 Mathematics Trigonometrical Equations Relation between sides and angles, Solutions of triangles

Easy

In $\Delta ABC$,$\frac{\sin B}{\sin (A + B)} = $

A
$\frac{b}{a + b}$
B
$\frac{b}{c}$
C
$\frac{c}{b}$
D
None of these

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Relation between sides and angles, Solutions of triangles

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MediumMHT CET 2020

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DifficultMHT CET 2024

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MediumAP EAMCET 2022

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Easy

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In $\Delta ABC$,$\frac{\sin B}{\sin (A + B)} = $

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