In $\triangle ABC$,$(a-b)^2 \sin^2\left(\frac{A+B}{2}\right) + (a+b)^2 \sin^2\left(\frac{C}{2}\right) = $

  • A
    $b^2$
  • B
    $a^2$
  • C
    $c^2$
  • D
    $a^2+b^2-c^2$

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