In $\triangle ABC$,if $a: b: c = 4: 5: 6$,then the ratio between the circumradius and the inradius is

  • A
    $\frac{16}{7}$
  • B
    $\frac{16}{9}$
  • C
    $\frac{7}{16}$
  • D
    $\frac{11}{7}$

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