(B) In a $ccp$ lattice,the number of $X$ atoms at the corners is $8 \times \frac{1}{8} = 1$. Since one $X$ atom is replaced by $Z$,the number of $X$ a

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(B) In a $ccp$ lattice,the number of $X$ atoms at the corners is $8 \times \frac{1}{8} = 1$. Since one $X$ atom is replaced by $Z$,the number of $X$ atoms remaining is $1 - \frac{1}{8} = \frac{7}{8}$. The number of $Z$ atoms is $\frac{1}{8}$. The number of $Y$ atoms at the face centers is $6 \times \frac{1}{2} = 3$. The ratio of $X:Y:Z$ is $\frac{7}{8} : 3 : \frac{1}{8}$. Multiplying by $8$,we get $7 : 24 : 1$. Thus,the formula is $X_7Y_{24}Z$.

Class 12 Chemistry Solid State Crystal structure and Coordination number

Medium

In a $ccp$ lattice of $X$ and $Y$,$X$ atoms are present at the corners while $Y$ atoms are at face centers. What would be the formula of the compound if one of the $X$ atoms from a corner is replaced by a $Z$ atom?

A
$X_7Y_{24}Z_2$
B
$X_7Y_{24}Z$
C
$X_{24}Y_7Z$
D
$XY_{24}Z$

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Class 12

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Solid State

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Crystal structure and Coordination number

In sodium chloride crystal,the number of next nearest neighbours of each $Na^{+}$ ion is

Medium

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If three elements $X$,$Y$ and $Z$ crystallise in a $ccp$ lattice with $X$ atoms at the corners,$Y$ atoms at the cube centre and $Z$ atoms at the edges centre,the formula of the compound will be

Medium

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$A$ solid $AB$ crystallises in $NaCl$ structure. The anion $B$ forms $fcc$ lattice,while the cation $A^{+}$ occupies all the octahedral holes. If all the particles along a diagonal plane (as shown in the figure) are removed,then the formula of the solid becomes

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$A$ compound is formed by elements $A$ and $B$. This crystallizes in a cubic structure where atoms $A$ are at the corners of the cube and atoms $B$ are at the body center. The simplest formula of the compound is:

MediumAIPMT 2000

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In a cubic crystal structure,'$W$' atoms are at the corners of the cube,'$O$' atoms are at the edges,and '$Na$' atoms are at the body center. Determine the formula of this crystal.

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In a $ccp$ lattice of $X$ and $Y$,$X$ atoms are present at the corners while $Y$ atoms are at face centers. What would be the formula of the compound if one of the $X$ atoms from a corner is replaced by a $Z$ atom?

Similar Questions

In sodium chloride crystal,the number of next nearest neighbours of each $Na^{+}$ ion is

If three elements $X$,$Y$ and $Z$ crystallise in a $ccp$ lattice with $X$ atoms at the corners,$Y$ atoms at the cube centre and $Z$ atoms at the edges centre,the formula of the compound will be

$A$ solid $AB$ crystallises in $NaCl$ structure. The anion $B$ forms $fcc$ lattice,while the cation $A^{+}$ occupies all the octahedral holes. If all the particles along a diagonal plane (as shown in the figure) are removed,then the formula of the solid becomes

$A$ compound is formed by elements $A$ and $B$. This crystallizes in a cubic structure where atoms $A$ are at the corners of the cube and atoms $B$ are at the body center. The simplest formula of the compound is:

In a cubic crystal structure,'$W$' atoms are at the corners of the cube,'$O$' atoms are at the edges,and '$Na$' atoms are at the body center. Determine the formula of this crystal.

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