In a Delta ABC,a semicircle is inscribed,whos | vedclass

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(A) Let the radius of the semicircle be $r$. The center of the semicircle lies on side $AB$ (side $c$).Let the center be $I$. The semicircle is tangen

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$\frac{2\Delta}{a + b}$

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(A) Let the radius of the semicircle be $r$. The center of the semicircle lies on side $AB$ (side $c$).Let the center be $I$. The semicircle is tangent to sides $AC$ and $BC$.Thus,the distance from $I$ to $AC$ is $r$ and the distance from $I$ to $BC$ is $r$.The area of $\Delta ABC$ can be expressed as the sum of the areas of $\Delta AIC$ and $\Delta BIC$.$\Delta = 	ext{Area}(\Delta AIC) + 	ext{Area}(\Delta BIC)$$\Delta = \frac{1}{2} 	imes AC 	imes r + \frac{1}{2} 	imes BC 	imes r$$\Delta = \frac{1}{2} 	imes b 	imes r + \frac{1}{2} 	imes a 	imes r$$\Delta = \frac{r}{2} (a + b)$$r = \frac{2\Delta}{a + b}$

In a $\Delta ABC$,a semicircle is inscribed,whose diameter lies on the side $c$. Then the radius of the semicircle is
Where $\Delta$ is the area of the triangle $ABC$.

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In a $\Delta ABC$,a semicircle is inscribed,whose diameter lies on the side $c$. Then the radius of the semicircle isWhere $\Delta$ is the area of the triangle $ABC$.