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(C) The height of the liquid column in a capillary tube is given by the formula $h = \frac{2T \cos 	heta}{r ho g}$, where $T$ is surface tension, $

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$30 	ext{ cm}$

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(C) The height of the liquid column in a capillary tube is given by the formula $h = \frac{2T \cos 	heta}{r ho g}$, where $T$ is surface tension, $	heta$ is the contact angle, $r$ is the radius of the tube, $ho$ is the density of the liquid, and $g$ is the acceleration due to gravity.In a freely falling elevator, the effective acceleration due to gravity $g_{	ext{eff}} = g - a$. Since the elevator is in free fall, $a = g$, therefore $g_{	ext{eff}} = 0$.As $h \propto \frac{1}{g_{	ext{eff}}}$, when $g_{	ext{eff}} = 0$, the height $h$ tends to infinity.However, the water will rise until it reaches the top of the capillary tube. Since the tube is $30 	ext{ cm}$ long, the water column will fill the entire tube.

In a capillary tube experiment, a vertical $30 \text{ cm}$ long capillary tube is dipped in water. Water rises up to a height of $10 \text{ cm}$ due to capillarity. If this experiment is conducted in a freely falling elevator, then the length of the water column becomes

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