In a certain office,72 % of the workers prefe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the total number of workers be $x$.Let $C$ be the set of workers who prefer cold drink and $T$ be the set of workers who prefer tea.Given: $n(

Vedclass · Accepted Answer

$250$

Vedclass · Answer

(B) Let the total number of workers be $x$.Let $C$ be the set of workers who prefer cold drink and $T$ be the set of workers who prefer tea.Given: $n(C) = 72 \% 	ext{ of } x$,$n(T) = 44 \% 	ext{ of } x$.Since every worker prefers at least one drink,$n(C \cup T) = 100 \% 	ext{ of } x$.We know that $n(C \cup T) = n(C) + n(T) - n(C \cap T)$.Substituting the values: $100 \% = 72 \% + 44 \% - n(C \cap T) \%$.$100 \% = 116 \% - n(C \cap T) \%$.Therefore,$n(C \cap T) = 116 \% - 100 \% = 16 \%$.It is given that $40$ workers like both,so $16 \% 	ext{ of } x = 40$.$x = \frac{40 	imes 100}{16} = 250$.Thus,the total number of workers is $250$.

In a certain office,$72 \%$ of the workers prefer cold drink and $44 \%$ prefer tea. If each of them prefers cold drink or tea and $40$ like both,then the total number of workers in the office is

Similar Questions

Out of $100$ families in the neighbourhood,$50$ have radios,$75$ have $TVs$ and $25$ have $VCRs$. Only $10$ families have all three and each $VCR$ owner also has a $TV$. If some families have radio only,how many have only $TV$?

If $n(A) = 3$ and $n(B) = 6$ and $A \subseteq B$,then the number of elements in $A \cap B$ is equal to

Let $A = \{(x, y) : y = e^x, x \in R\}$ and $B = \{(x, y) : y = e^{-x}, x \in R\}$. Then:

Domain of the function $\frac{\sqrt{1 + x} - \sqrt{1 - x}}{x}$ is

If $aN = \{ ax : x \in N \}$,then the set $3N \cap 7N$ is equal to .....$N$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module