In a circle with radius $11.2 \, cm$,two radii are perpendicular to each other. Find the area of the minor sector,the major sector,and the minor segment corresponding to these radii.

(N/A) Given: Radius $r = 11.2 \, cm$,Central angle $\theta = 90^{\circ}$.
Area of the circle $A = \pi r^2 = \frac{22}{7} \times 11.2 \times 11.2 = 394.24 \, cm^2$.
Area of the minor sector $= \frac{\theta}{360^{\circ}} \times \pi r^2 = \frac{90}{360} \times 394.24 = \frac{1}{4} \times 394.24 = 98.56 \, cm^2$.
Area of the major sector $=$ Area of circle $-$ Area of minor sector $= 394.24 - 98.56 = 295.68 \, cm^2$.
Area of the minor segment $=$ Area of minor sector $-$ Area of $\triangle OAB = 98.56 - (\frac{1}{2} \times r^2 \times \sin 90^{\circ}) = 98.56 - (0.5 \times 11.2 \times 11.2 \times 1) = 98.56 - 62.72 = 35.84 \, cm^2$.