In a circle with radius 13 , cm,find the leng | vedclass

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(B) Let the circle have centre $O$ and radius $r = 13 \, cm$. Let $AB$ be the chord at a distance $OM = 12 \, cm$ from the centre,where $OM \perp AB$.

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$10$

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(B) Let the circle have centre $O$ and radius $r = 13 \, cm$. Let $AB$ be the chord at a distance $OM = 12 \, cm$ from the centre,where $OM \perp AB$.In the right-angled triangle $	riangle OMA$,by the Pythagorean theorem:$OA^2 = OM^2 + AM^2$$13^2 = 12^2 + AM^2$$169 = 144 + AM^2$$AM^2 = 169 - 144 = 25$$AM = \sqrt{25} = 5 \, cm$.Since the perpendicular from the centre to a chord bisects the chord,the length of the chord $AB = 2 	imes AM = 2 	imes 5 = 10 \, cm$.

In a circle with radius $13 \, cm$,find the length of a chord lying at a distance of $12 \, cm$ from the centre. (in $, cm$)

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