In a common base mode of a transistor,the col | vedclass

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(B) Given: Collector current $I_C = 5.488 \ mA$ and Emitter current $I_E = 5.60 \ mA$.First,calculate the base current $I_B$ using the relation $I_B =

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$49$

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(B) Given: Collector current $I_C = 5.488 \ mA$ and Emitter current $I_E = 5.60 \ mA$.First,calculate the base current $I_B$ using the relation $I_B = I_E - I_C$.$I_B = 5.60 \ mA - 5.488 \ mA = 0.112 \ mA$.The base current amplification factor $\beta$ is defined as the ratio of collector current to base current: $\beta = \frac{I_C}{I_B}$.Substituting the values: $\beta = \frac{5.488}{0.112} = 49$.Thus,the value of $\beta$ is $49$.

In a common base mode of a transistor,the collector current is $5.488 \ mA$ for an emitter current of $5.60 \ mA$. The value of the base current amplification factor $(\beta)$ will be

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