The relation between alpha and beta parameter | vedclass

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(B) In a transistor,the emitter current $i_e$ is the sum of the base current $i_b$ and the collector current $i_c$: $i_e = i_b + i_c$ Dividing both si

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$\alpha = \frac{\beta}{1 + \beta}$

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(B) In a transistor,the emitter current $i_e$ is the sum of the base current $i_b$ and the collector current $i_c$: $i_e = i_b + i_c$ Dividing both sides by $i_c$: $\frac{i_e}{i_c} = \frac{i_b}{i_c} + 1$ We know that $\alpha = \frac{i_c}{i_e}$ (so $\frac{i_e}{i_c} = \frac{1}{\alpha}$) and $\beta = \frac{i_c}{i_b}$ (so $\frac{i_b}{i_c} = \frac{1}{\beta}$). Substituting these values: $\frac{1}{\alpha} = \frac{1}{\beta} + 1$ $\frac{1}{\alpha} = \frac{1 + \beta}{\beta}$ Therefore,$\alpha = \frac{\beta}{1 + \beta}$.

The relation between $\alpha$ and $\beta$ parameters of current gains for a transistor is given by:

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