In a common emitter configuration, a transistor has $\beta=50$ and input resistance $1 \text{ k}\Omega$. If the peak value of a.c. input is $0.01 \text{ V}$, then the peak value of collector current is: (in $\mu\text{A}$)

In a common emitter amplifier,a change of $0.2 \text{ mA}$ in the base current causes a change of $5 \text{ mA}$ in the collector current. If the input resistance is $2 \text{ k}\Omega$ and the voltage gain is $75$,what is the load resistance used in the circuit?

The phase difference between input and output voltage of a $CE$ circuit is.....$^o$

In an $n-p-n$ transistor amplifier,the collector current is $8 \ mA$. If $80 \%$ of the electrons from the emitter reach the collector,then ($\alpha$ and $\beta$ are current ratios):

The input resistance of a common-emitter amplifier is $2 \, k\Omega$ and a.c. current gain is $20$. If the load resistor used is $5 \, k\Omega$,calculate the transconductance of the transistor used in $\Omega^{-1}$.

In a transistor amplifier, a change of $0.2 \text{ mA}$ in the base current causes a change of $5 \text{ mA}$ in the collector current. If input resistance is $2 \text{ k}\Omega$ and voltage gain is $75$, the load resistance used in the circuit is