For a hollow spherical shell,how does the pot | vedclass

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(B) For a hollow spherical shell of radius $R$ carrying charge $Q$:$1$. Inside the shell $(r \le R)$,the electric field is zero,which implies that the

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(B) For a hollow spherical shell of radius $R$ carrying charge $Q$:$1$. Inside the shell $(r \le R)$,the electric field is zero,which implies that the potential is constant and equal to the potential at the surface: $V_{inside} = \frac{Q}{4\pi \varepsilon_0 R}$.$2$. Outside the shell $(r \ge R)$,the shell behaves like a point charge placed at the centre,so the potential varies as $V_{out} = \frac{Q}{4\pi \varepsilon_0 r}$,which means $V \propto \frac{1}{r}$.$3$. Comparing this with the given options,Graph $B$ correctly shows a constant potential for $r \le R$ and a hyperbolic decrease for $r > R$.

For a hollow spherical shell,how does the potential $(V)$ change with respect to the distance $(r)$ from the centre?

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