In a horse race,the odds in favour of three h | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The odds in favour of the three horses are $1:2$,$1:3$,and $1:4$.The probabilities of winning for the three horses are $P(A) = \frac{1}{1+2} = \fr

Vedclass · Accepted Answer

$\frac{47}{60}$

Vedclass · Answer

(B) The odds in favour of the three horses are $1:2$,$1:3$,and $1:4$.The probabilities of winning for the three horses are $P(A) = \frac{1}{1+2} = \frac{1}{3}$,$P(B) = \frac{1}{1+3} = \frac{1}{4}$,and $P(C) = \frac{1}{1+4} = \frac{1}{5}$.Since these are mutually exclusive events (only one horse can win),the probability that one of the horses will win is the sum of their individual probabilities:$P(A \cup B \cup C) = P(A) + P(B) + P(C) = \frac{1}{3} + \frac{1}{4} + \frac{1}{5}$.Taking the least common multiple of $3, 4, 5$,which is $60$:$P = \frac{20 + 15 + 12}{60} = \frac{47}{60}$.

In a horse race,the odds in favour of three horses are $1:2$,$1:3$,and $1:4$. The probability that one of the horses will win the race is

Similar Questions

If the odds against $A$ solving a problem are $4:3$ and the odds in favor of $B$ solving the problem are $7:5$,what is the probability that only one of them solves the problem?

An event has odds in favour $4 : 5$. Then,the probability that the event occurs is:

If $P(A) = 0.4$,$P(B) = x$,$P(A \cup B) = 0.7$ and the events $A$ and $B$ are independent,then $x =$

In class $XI$ of a school,$40\%$ of the students study Mathematics and $30\%$ study Biology. $10\%$ of the class study both Mathematics and Biology. If a student is selected at random from the class,find the probability that they will be studying Mathematics or Biology.

Two dice are thrown simultaneously. The probability that the sum is odd or less than $7$ or both is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module