In class XI of a school,40% of the students s | vedclass

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Question

(A) Let $A$ be the event that the selected student studies Mathematics and $B$ be the event that the selected student studies Biology.Given:$P(A) = 40

Vedclass · Accepted Answer

$0.6$

Vedclass · Answer

(A) Let $A$ be the event that the selected student studies Mathematics and $B$ be the event that the selected student studies Biology.Given:$P(A) = 40\% = \frac{40}{100} = 0.4$$P(B) = 30\% = \frac{30}{100} = 0.3$$P(A \cap B) = 10\% = \frac{10}{100} = 0.1$We need to find the probability that the student studies Mathematics or Biology,which is $P(A \cup B)$.Using the addition theorem of probability:$P(A \cup B) = P(A) + P(B) - P(A \cap B)$$P(A \cup B) = 0.4 + 0.3 - 0.1$$P(A \cup B) = 0.6$Thus,the probability that the selected student studies Mathematics or Biology is $0.6$.

In class $XI$ of a school,$40\%$ of the students study Mathematics and $30\%$ study Biology. $10\%$ of the class study both Mathematics and Biology. If a student is selected at random from the class,find the probability that they will be studying Mathematics or Biology.

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