(A) Given that $A$ and $B$ are independent events,we have $P(A \cap B) = P(A) \times P(B)$.Substituting the given values: $P(A \cap B) = 0.3 \times 0.

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(A) Given that $A$ and $B$ are independent events,we have $P(A \cap B) = P(A) \times P(B)$.Substituting the given values: $P(A \cap B) = 0.3 \times 0.4 = 0.12$.Using the addition theorem of probability: $P(A \cup B) = P(A) + P(B) - P(A \cap B)$.Substituting the values: $P(A \cup B) = 0.3 + 0.4 - 0.12 = 0.58$.

Class 11 Mathematics Probability Odds in favor and odds against, Addition theorem on probability

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Let $A$ and $B$ be independent events with $P(A)=0.3$ and $P(B)=0.4$. Find $P(A \cup B)$.

A
$0.58$
B
$0.62$
C
$0.70$
D
$0.12$

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Probability

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Odds in favor and odds against, Addition theorem on probability

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Let $A$ and $B$ be independent events with $P(A)=0.3$ and $P(B)=0.4$. Find $P(A \cup B)$.

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